What is (4-2i)/(2+i)+(2i)/(1-i) ?

The solution to (4-2i)/(2+i)+(2i)/(1-i) is 1/5-3/5 i

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simplify (4-2i)/(2+i)+(2i)/(1-i)

simplify

\frac{4 - 2 i}{2 + i} + \frac{2 i}{1 - i}

\frac{1}{5} - \frac{3}{5} i

Solution steps

\frac{4 - 2 i}{2 + i} + \frac{2 i}{1 - i}

\frac{4 - 2 i}{2 + i} = \frac{6 - 8 i}{5}

\frac{2 i}{1 - i} = i - 1

= \frac{6 - 8 i}{5} + i - 1

Join

\frac{6 - 8 i}{5} + i - 1 : \frac{- 3 i + 1}{5}

= \frac{- 3 i + 1}{5}

Rewrite in standard complex form:

\frac{1}{5} - \frac{3}{5} i

= \frac{1}{5} - \frac{3}{5} i

1^{3}

5 x - 6 x

(- 3125)^{\frac{1}{5}}

3^{3 - 1}

(z + 3)^{2}

What is (4-2i)/(2+i)+(2i)/(1-i) ?
The solution to (4-2i)/(2+i)+(2i)/(1-i) is 1/5-3/5 i