What is ((2x^2+x-3))/((x-1)) ?

The solution to ((2x^2+x-3))/((x-1)) is 2x+3

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simplify ((2x^2+x-3))/((x-1))

simplify

\frac{( 2 x ^{2} + x - 3 )}{( x - 1 )}

2 x + 3

Solution steps

\frac{2 x ^{2} + x - 3}{x - 1}

Factor

2 x^{2} + x - 3 : (x - 1) (2 x + 3)

= \frac{( x - 1 ) ( 2 x + 3 )}{x - 1}

Cancel the common factor:

x - 1

= 2 x + 3

lo g_{3} (3^{\frac{1}{4}})

(4 x + 7) (x - 2) (x - 1) (x - 1)

- a^{2} b - a^{2} b - 3 a^{2} b

lo g_{a} (\frac{1}{a ^{5}})

6 x + 4 x