What is factor 2x^3-5x^2-4x+12 ?

The solution to factor 2x^3-5x^2-4x+12 is (x-2)^2(2x+3)

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factor 2x^3-5x^2-4x+12

factor

2 x^{3} - 5 x^{2} - 4 x + 12

(x - 2)^{2} (2 x + 3)

Solution steps

2 x^{3} - 5 x^{2} - 4 x + 12

Use the rational root theorem

= (x - 2) \frac{2 x ^{3} - 5 x ^{2} - 4 x + 12}{x - 2}

\frac{2 x ^{3} - 5 x ^{2} - 4 x + 12}{x - 2} = 2 x^{2} - x - 6

= (x - 2) (2 x^{2} - x - 6)

Factor

2 x^{2} - x - 6 : (2 x + 3) (x - 2)

= (x - 2) (2 x + 3) (x - 2)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (x - 2)^{2} (2 x + 3)

(x - 1 - 3 i) (x - 1 + 3 i)

\frac{6 x ^{3}}{2 x ^{2}}

(2 + y)^{3}

\frac{7}{7 x} + \frac{9}{7 x}

m (m - 4) (m - 6) (3 m + 2)

What is factor 2x^3-5x^2-4x+12 ?
The solution to factor 2x^3-5x^2-4x+12 is (x-2)^2(2x+3)