What are the solutions to the equation x^2+4=4 ?

The solutions to the equation x^2+4=4 are x=0

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x^2+4=4

x^{2} + 4 = 4

x = 0

Solution steps

x^{2} + 4 = 4

Move

4

to the right side

x^{2} = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

x = 0

\frac{32 x ^{3} y}{5 x y ^{2}} \cdot \frac{15 y}{8 x ^{2} y ^{4}}

1014

\frac{x + 8}{x - 7} \leq 1

\frac{8 y}{3} - \frac{2 y}{4} < - 13

(\frac{1}{2})^{0}

What are the solutions to the equation x^2+4=4 ?
The solutions to the equation x^2+4=4 are x=0
Find the zeros of x^2+4=4
The zeros of x^2+4=4 are x=0