What is factor 1-4x+4x^2 ?

The solution to factor 1-4x+4x^2 is (2x-1)^2

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factor 1-4x+4x^2

factor

1 - 4 x + 4 x^{2}

(2 x - 1)^{2}

Solution steps

1 - 4 x + 4 x^{2}

Write in the standard form

= 4 x^{2} - 4 x + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 x^{2} = (2 x)^{2}

1 = 1^{2}

- 4 x = - 2 \cdot 2 x \cdot 1

= (2 x)^{2} - 2 \cdot 2 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 x)^{2} - 2 \cdot 2 x \cdot 1 + 1^{2} = (2 x - 1)^{2}

= (2 x - 1)^{2}

9 a^{2} b^{4}

2 e^{0.03}

18 a^{4}

6 \times \frac{3}{4}

17 \times 3