What are the solutions to the equation x^2-8x+16=1 ?

The solutions to the equation x^2-8x+16=1 are x=5,x=3

Find the zeros of x^2-8x+16=1

The zeros of x^2-8x+16=1 are x=5,x=3

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x^{2} - 8 x + 16 = 1

x = 5, x = 3

Solution steps

x^{2} - 8 x + 16 = 1

Move

1

to the left side

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

\frac{5}{12} x + 1 < - 2 (1 - \frac{1}{8} x) + 3

∣ x - 4 ∣ < 13

3 \cdot 3^{\frac{1}{3}}

8 x - 3 = 0

\frac{k - 13}{5} \leq - 3

What are the solutions to the equation x^2-8x+16=1 ?
The solutions to the equation x^2-8x+16=1 are x=5,x=3
Find the zeros of x^2-8x+16=1
The zeros of x^2-8x+16=1 are x=5,x=3