What is (6x^2-(3y^3)/5)^2 ?

The solution to (6x^2-(3y^3)/5)^2 is ((30x^2-3y^3)^2)/(25)

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simplify (6x^2-(3y^3)/5)^2

simplify

(6 x^{2} - \frac{3 y ^{3}}{5})^{2}

\frac{( 30 x ^{2} - 3 y ^{3} ) ^{2}}{25}

Solution steps

(6 x^{2} - \frac{3 y ^{3}}{5})^{2}

Join

6 x^{2} - \frac{3 y ^{3}}{5} : \frac{30 x ^{2} - 3 y ^{3}}{5}

= (\frac{30 x ^{2} - 3 y ^{3}}{5})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 30 x ^{2} - 3 y ^{3} ) ^{2}}{5 ^{2}}

5^{2} = 25

= \frac{( 30 x ^{2} - 3 y ^{3} ) ^{2}}{25}

16 w^{2} y - 49 a^{2} y

10 + (- 9)

- 4 \times 5

- \frac{1}{4} + 3

\frac{1}{16} - \frac{3}{4}

What is (6x^2-(3y^3)/5)^2 ?
The solution to (6x^2-(3y^3)/5)^2 is ((30x^2-3y^3)^2)/(25)