What is (-4x^2y+3xy^2-1/2)+(9xy^2-1/4 x^2y+5/3) ?

The solution to (-4x^2y+3xy^2-1/2)+(9xy^2-1/4 x^2y+5/3) is -(17x^2y)/4+12xy^2+7/6

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simplify (-4x^2y+3xy^2-1/2)+(9xy^2-1/4 x^2y+5/3)

simplify

(- 4 x^{2} y + 3 x y^{2} - \frac{1}{2}) + (9 x y^{2} - \frac{1}{4} x^{2} y + \frac{5}{3})

- \frac{17 x ^{2} y}{4} + 12 x y^{2} + \frac{7}{6}

Solution steps

(- 4 x^{2} y + 3 x y^{2} - \frac{1}{2}) + (9 x y^{2} - \frac{1}{4} x^{2} y + \frac{5}{3})

Simplify

(- 4 x^{2} y + 3 x y^{2} - \frac{1}{2}) + (9 x y^{2} - \frac{1}{4} x^{2} y + \frac{5}{3}) : - 4 x^{2} y + 3 x y^{2} - \frac{1}{2} + 9 x y^{2} - \frac{1}{4} x^{2} y + \frac{5}{3}

= - 4 x^{2} y + 3 x y^{2} - \frac{1}{2} + 9 x y^{2} - \frac{1}{4} x^{2} y + \frac{5}{3}

Add similar elements:

3 x y^{2} + 9 x y^{2} = 12 x y^{2}

= - 4 x^{2} y + 12 x y^{2} - \frac{1}{2} - \frac{1}{4} x^{2} y + \frac{5}{3}

Factor out common term

x^{2} y : x^{2} y (- 4 - \frac{1}{4})

= x^{2} y (- 4 - \frac{1}{4}) + 12 x y^{2} - \frac{1}{2} + \frac{5}{3}

Simplify

x^{2} y (- 4 - \frac{1}{4}) : - x^{2} y \frac{17}{4}

= - x^{2} y \frac{17}{4} + 12 x y^{2} - \frac{1}{2} + \frac{5}{3}

Join

- x^{2} y \frac{17}{4} + 12 x y^{2} - \frac{1}{2} + \frac{5}{3} : - \frac{17}{4} x^{2} y + 12 x y^{2} + \frac{7}{6}

= - \frac{17}{4} x^{2} y + 12 x y^{2} + \frac{7}{6}

Simplify

- \frac{17}{4} x^{2} y : - \frac{17 x ^{2} y}{4}

= - \frac{17 x ^{2} y}{4} + 12 x y^{2} + \frac{7}{6}

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2 (3 r + 7) - (2 + r)

\frac{( \frac{1}{x + 1} - \frac{1}{x - 1} )}{( \frac{1}{x - 1} + \frac{1}{x + 1} )}

1.0 2^{12}

\frac{x ^{2} - 2 x - 15}{x ^{2} - 13 x + 40}

What is (-4x^2y+3xy^2-1/2)+(9xy^2-1/4 x^2y+5/3) ?
The solution to (-4x^2y+3xy^2-1/2)+(9xy^2-1/4 x^2y+5/3) is -(17x^2y)/4+12xy^2+7/6