What is (m^2+n^2)/(m^4-n^4) ?

The solution to (m^2+n^2)/(m^4-n^4) is 1/(m^2-n^2)

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simplify (m^2+n^2)/(m^4-n^4)

simplify

\frac{m ^{2} + n ^{2}}{m ^{4} - n ^{4}}

\frac{1}{m ^{2} - n ^{2}}

Solution steps

\frac{m ^{2} + n ^{2}}{m ^{4} - n ^{4}}

Factor

m^{4} - n^{4} : (m^{2} + n^{2}) (m^{2} - n^{2})

= \frac{m ^{2} + n ^{2}}{( m ^{2} + n ^{2} ) ( m ^{2} - n ^{2} )}

Cancel the common factor:

m^{2} + n^{2}

= \frac{1}{m ^{2} - n ^{2}}

\frac{2 x ^{2} - 12 x}{x ^{2} - 36}

(122)^{2}

3 x^{2} + 6 x^{2}

2 u^{2} v - 20 u v^{2} + 50 v^{3}

What is (m^2+n^2)/(m^4-n^4) ?
The solution to (m^2+n^2)/(m^4-n^4) is 1/(m^2-n^2)