What are the solutions to the equation 3x^2-42=0 ?

The solutions to the equation 3x^2-42=0 are x=sqrt(14),x=-sqrt(14)

Find the zeros of 3x^2-42=0

The zeros of 3x^2-42=0 are x=sqrt(14),x=-sqrt(14)

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3 x^{2} - 42 = 0

x = 14, x = - 14

Solution steps

3 x^{2} - 42 = 0

Move

42

to the right side

3 x^{2} = 42

Divide both sides by

3

x^{2} = 14

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 14, x = - 14

x^{2} - 16 + 64

- 3 - 2 x > 9

w + 16 < 4

- \frac{x}{9} = 5

4 x^{2} + x - 6 = 0

What are the solutions to the equation 3x^2-42=0 ?
The solutions to the equation 3x^2-42=0 are x=sqrt(14),x=-sqrt(14)
Find the zeros of 3x^2-42=0
The zeros of 3x^2-42=0 are x=sqrt(14),x=-sqrt(14)