What is (x^2+2x-80)/(2x^3-24x^2+64x) ?

The solution to (x^2+2x-80)/(2x^3-24x^2+64x) is (x+10)/(2x(x-4))

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simplify (x^2+2x-80)/(2x^3-24x^2+64x)

simplify

\frac{x ^{2} + 2 x - 80}{2 x ^{3} - 24 x ^{2} + 64 x}

\frac{x + 10}{2 x ( x - 4 )}

Solution steps

\frac{x ^{2} + 2 x - 80}{2 x ^{3} - 24 x ^{2} + 64 x}

Factor

x^{2} + 2 x - 80 : (x - 8) (x + 10)

= \frac{( x - 8 ) ( x + 10 )}{2 x ^{3} - 24 x ^{2} + 64 x}

Factor

2 x^{3} - 24 x^{2} + 64 x : 2 x (x - 4) (x - 8)

= \frac{( x - 8 ) ( x + 10 )}{2 x ( x - 4 ) ( x - 8 )}

Cancel the common factor:

x - 8

= \frac{x + 10}{2 x ( x - 4 )}

\frac{3}{3} + 1

lo g_{10} (1.25)

(x + \frac{1}{3})^{2}

\frac{2 - 3 i}{2 + 3 i}

lo g_{\frac{1}{10}} (x)

What is (x^2+2x-80)/(2x^3-24x^2+64x) ?
The solution to (x^2+2x-80)/(2x^3-24x^2+64x) is (x+10)/(2x(x-4))