What is ((a+\frac{2a)/(a-1))}{(a-(2a)/(a-1))} ?

The solution to ((a+\frac{2a)/(a-1))}{(a-(2a)/(a-1))} is (a+1)/(a-3)

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simplify ((a+\frac{2a)/(a-1))}{(a-(2a)/(a-1))}

simplify

\frac{( a + \frac{2 a}{a - 1} )}{( a - \frac{2 a}{a - 1} )}

\frac{a + 1}{a - 3}

Solution steps

\frac{a + \frac{2 a}{a - 1}}{a - \frac{2 a}{a - 1}}

Join

a + \frac{2 a}{a - 1} : \frac{a ^{2} + a}{a - 1}

= \frac{\frac{a ^{2} + a}{a - 1}}{a - \frac{2 a}{a - 1}}

Join

a - \frac{2 a}{a - 1} : \frac{a ^{2} - 3 a}{a - 1}

= \frac{\frac{a ^{2} + a}{a - 1}}{\frac{a ^{2} - 3 a}{a - 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( a ^{2} + a ) ( a - 1 )}{( a - 1 ) ( a ^{2} - 3 a )}

Cancel

\frac{( a ^{2} + a ) ( a - 1 )}{( a - 1 ) ( a ^{2} - 3 a )} : \frac{a + 1}{a - 3}

= \frac{a + 1}{a - 3}

(- 2 w) (- 7 w^{4})

lo g_{10} (x^{5})

\frac{- 4 + 10 i}{3 + 4 i}

(x + 3)^{2} - 5

(x + 3)^{2} - 9

What is ((a+\frac{2a)/(a-1))}{(a-(2a)/(a-1))} ?
The solution to ((a+\frac{2a)/(a-1))}{(a-(2a)/(a-1))} is (a+1)/(a-3)