What is ((x^4-16))/((x+2)) ?

The solution to ((x^4-16))/((x+2)) is (x^2+4)(x-2)

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simplify ((x^4-16))/((x+2))

simplify

\frac{( x ^{4} - 16 )}{( x + 2 )}

(x^{2} + 4) (x - 2)

Solution steps

\frac{x ^{4} - 16}{x + 2}

Apply exponent rules

= \frac{( x ^{2} ) ^{2} - 4 ^{2}}{x + 2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{2})^{2} - 4^{2} = (x^{2} + 4) (x^{2} - 4)

= \frac{( x ^{2} + 4 ) ( x ^{2} - 4 )}{x + 2}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x ^{2} + 4 ) ( x + 2 ) ( x - 2 )}{x + 2}

Cancel the common factor:

x + 2

= (x^{2} + 4) (x - 2)

lo g_{2} (\frac{1}{3}) + lo g_{2} (3)

\frac{124}{3}

\frac{2}{3} \cdot \frac{1}{6}

4 x^{8}

22 \times 22