What is (2x^{-1}-3x^{-2})/(4x^{-3)} ?

The solution to (2x^{-1}-3x^{-2})/(4x^{-3)} is (x(2x-3))/4

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simplify (2x^{-1}-3x^{-2})/(4x^{-3)}

simplify

\frac{2 x ^{- 1} - 3 x ^{- 2}}{4 x ^{- 3}}

\frac{x ( 2 x - 3 )}{4}

Solution steps

\frac{2 x ^{- 1} - 3 x ^{- 2}}{4 x ^{- 3}}

Multiply

4 x^{- 3} : \frac{4}{x ^{3}}

= \frac{2 x ^{- 1} - 3 x ^{- 2}}{\frac{4}{x ^{3}}}

2 x^{- 1} = \frac{2}{x}

3 x^{- 2} = \frac{3}{x ^{2}}

= \frac{\frac{2}{x} - \frac{3}{x ^{2}}}{\frac{4}{x ^{3}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( \frac{2}{x} - \frac{3}{x ^{2}} ) x ^{3}}{4}

Join

\frac{2}{x} - \frac{3}{x ^{2}} : \frac{2 x - 3}{x ^{2}}

= \frac{\frac{2 x - 3}{x ^{2}} x ^{3}}{4}

Multiply

\frac{2 x - 3}{x ^{2}} x^{3} : x (2 x - 3)

= \frac{x ( 2 x - 3 )}{4}

(2 x - 5)^{4}

4^{- 1.5}

4 m - 3 + 2 m + 5

1.0 1^{12}

\frac{n ^{2}}{n}

What is (2x^{-1}-3x^{-2})/(4x^{-3)} ?
The solution to (2x^{-1}-3x^{-2})/(4x^{-3)} is (x(2x-3))/4