What is factor 5x^3+29x^2+19x-5 ?

The solution to factor 5x^3+29x^2+19x-5 is (x+1)(5x-1)(x+5)

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factor 5x^3+29x^2+19x-5

factor

5 x^{3} + 29 x^{2} + 19 x - 5

(x + 1) (5 x - 1) (x + 5)

Solution steps

5 x^{3} + 29 x^{2} + 19 x - 5

Use the rational root theorem

= (x + 1) \frac{5 x ^{3} + 29 x ^{2} + 19 x - 5}{x + 1}

\frac{5 x ^{3} + 29 x ^{2} + 19 x - 5}{x + 1} = 5 x^{2} + 24 x - 5

= (x + 1) (5 x^{2} + 24 x - 5)

Factor

5 x^{2} + 24 x - 5 : (5 x - 1) (x + 5)

= (x + 1) (5 x - 1) (x + 5)

\frac{5}{6} (- 2 y + 3)

1 0^{l o g_{10} (11)}

\frac{( x ^{3} + y ^{3} )}{( x + y )}

- 5 (- 3)

\frac{7}{3 x ^{2} - 5 x - 2} + \frac{x}{3 x + 1} - \frac{1}{x - 2}

What is factor 5x^3+29x^2+19x-5 ?
The solution to factor 5x^3+29x^2+19x-5 is (x+1)(5x-1)(x+5)