What are the solutions to the equation 4x^2-7x=2 ?

The solutions to the equation 4x^2-7x=2 are x=2,x=-1/4

Find the zeros of 4x^2-7x=2

The zeros of 4x^2-7x=2 are x=2,x=-1/4

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4 x^{2} - 7 x = 2

x = 2, x = - \frac{1}{4}

Solution steps

4 x^{2} - 7 x = 2

Move

2

to the left side

4 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 (- 2) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 4}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 4}

x = \frac{- ( - 7 ) + 9}{2 \cdot 4} : 2

x = \frac{- ( - 7 ) - 9}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{4}

(x - 2)^{2} > (x + 2) - (x - 2) + 8

(1 + i) (1 + 2 i)

2 y - 7 \geq - 14

6 4^{\frac{1}{3}}

- 21 - 6 k \leq - 4 (2 k + 6) + 2 k

What are the solutions to the equation 4x^2-7x=2 ?
The solutions to the equation 4x^2-7x=2 are x=2,x=-1/4
Find the zeros of 4x^2-7x=2
The zeros of 4x^2-7x=2 are x=2,x=-1/4