What is (32p^5q^6)/(-8p^3q^2) ?

The solution to (32p^5q^6)/(-8p^3q^2) is -4p^2q^4

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simplify (32p^5q^6)/(-8p^3q^2)

simplify

\frac{32 p ^{5} q ^{6}}{- 8 p ^{3} q ^{2}}

- 4 p^{2} q^{4}

Solution steps

\frac{32 p ^{5} q ^{6}}{- 8 p ^{3} q ^{2}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{32 p ^{5} q ^{6}}{8 p ^{3} q ^{2}}

Divide the numbers:

\frac{32}{8} = 4

= \frac{4 p ^{5} q ^{6}}{p ^{3} q ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{p ^{5}}{p ^{3}} = p^{5 - 3}

= \frac{4 q ^{6} p ^{5 - 3}}{q ^{2}}

Subtract the numbers:

5 - 3 = 2

= \frac{4 p ^{2} q ^{6}}{q ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{q ^{6}}{q ^{2}} = q^{6 - 2}

= 4 p^{2} q^{6 - 2}

Subtract the numbers:

6 - 2 = 4

= - 4 p^{2} q^{4}

(x - 4 y)^{3}

(33)^{3}

\frac{1}{8} \div 6

t^{2} + t^{2}

x^{3} - 7 x^{2} + 16 x - 112

What is (32p^5q^6)/(-8p^3q^2) ?
The solution to (32p^5q^6)/(-8p^3q^2) is -4p^2q^4