What is log_{10}(121)+4log_{10}(33) ?

The solution to log_{10}(121)+4log_{10}(33) is log_{10}(121*33^4)

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simplify log_{10}(121)+4log_{10}(33)

simplify

lo g_{10} (121) + 4 lo g_{10} (33)

lo g_{10} (121 \cdot 3 3^{4})

Decimal Notation

8.15684 \dots

Solution steps

lo g_{10} (121) + 4 lo g_{10} (33)

lo g_{10} (121) = 2 lo g_{10} (11)

= 2 lo g_{10} (11) + 4 lo g_{10} (33)

2 lo g_{10} (11) = lo g_{10} (1 1^{2})

4 lo g_{10} (33) = lo g_{10} (3 3^{4})

= lo g_{10} (1 1^{2}) + lo g_{10} (3 3^{4})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (1 1^{2}) + lo g_{10} (3 3^{4}) = lo g_{10} (1 1^{2} \cdot 3 3^{4})

= lo g_{10} (1 1^{2} \cdot 3 3^{4})

1 1^{2} = 121

= lo g_{10} (121 \cdot 3 3^{4})

\frac{28 x ^{7} y ^{6} + 21 x ^{6} y ^{5}}{7 x ^{3} y ^{3}}

3 x^{2} + 5 x^{2}

3 \frac{3}{4} \div \frac{5}{7}

lo g_{10} (1 0^{10})

3^{2} - 4^{2}

What is log_{10}(121)+4log_{10}(33) ?
The solution to log_{10}(121)+4log_{10}(33) is log_{10}(121*33^4)