What are the solutions to the equation x^2=x+90 ?

The solutions to the equation x^2=x+90 are x=10,x=-9

Find the zeros of x^2=x+90

The zeros of x^2=x+90 are x=10,x=-9

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x^{2} = x + 90

x = 10, x = - 9

Solution steps

x^{2} = x + 90

Move

90

to the left side

x^{2} - 90 = x

Move

x

to the left side

x^{2} - 90 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 90 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 90) = 19

x_{1, 2} = \frac{- ( - 1 ) \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 19}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 19}{2 \cdot 1}

x = \frac{- ( - 1 ) + 19}{2 \cdot 1} : 10

x = \frac{- ( - 1 ) - 19}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 10, x = - 9

(64 x^{4})^{\frac{1}{2}}

(\frac{2}{3})^{2} + (\frac{2}{3})^{2}

\frac{2}{9} (x + 1) \leq \frac{x}{18} + \frac{2}{9}

(\frac{1}{4})^{- 3}

a^{2} - 5 a - 6

What are the solutions to the equation x^2=x+90 ?
The solutions to the equation x^2=x+90 are x=10,x=-9
Find the zeros of x^2=x+90
The zeros of x^2=x+90 are x=10,x=-9