What is (x^2-4)/(x^3-8) ?

The solution to (x^2-4)/(x^3-8) is (x+2)/(x^2+2x+4)

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simplify (x^2-4)/(x^3-8)

simplify

\frac{x ^{2} - 4}{x ^{3} - 8}

\frac{x + 2}{x ^{2} + 2 x + 4}

Solution steps

\frac{x ^{2} - 4}{x ^{3} - 8}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x - 2 )}{x ^{3} - 8}

Factor

x^{3} - 8 : (x - 2) (x^{2} + 2 x + 4)

= \frac{( x + 2 ) ( x - 2 )}{( x - 2 ) ( x ^{2} + 2 x + 4 )}

Cancel the common factor:

x - 2

= \frac{x + 2}{x ^{2} + 2 x + 4}

\frac{2}{3} \cdot 30

- 20 \div 5

x^{3} (x^{2} y)^{2}

- \frac{\frac{- 5}{3}}{( \frac{\frac{3}{4}}{( \frac{7}{2} - \frac{5}{3} )} )}