What is (x^3-4x^2+x+6)/(x+1) ?

The solution to (x^3-4x^2+x+6)/(x+1) is (x-2)(x-3)

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simplify (x^3-4x^2+x+6)/(x+1)

simplify

\frac{x ^{3} - 4 x ^{2} + x + 6}{x + 1}

(x - 2) (x - 3)

Solution steps

\frac{x ^{3} - 4 x ^{2} + x + 6}{x + 1}

Use the rational root theorem

= \frac{( x + 1 ) \frac{x ^{3} - 4 x ^{2} + x + 6}{x + 1}}{x + 1}

\frac{x ^{3} - 4 x ^{2} + x + 6}{x + 1} = x^{2} - 5 x + 6

= \frac{( x + 1 ) ( x ^{2} - 5 x + 6 )}{x + 1}

Factor

x^{2} - 5 x + 6 : (x - 2) (x - 3)

= \frac{( x + 1 ) ( x - 2 ) ( x - 3 )}{x + 1}

Cancel the common factor:

x + 1

= (x - 2) (x - 3)

(- 100)^{\frac{1}{2}}

(3 x^{2} + 2 x + 3 y^{3})^{2}

lo g_{2} (128)

(x^{6} - 1)^{2}

2 x^{2} + 6 x - 5 - 7 x^{2} + 3 x + 4

What is (x^3-4x^2+x+6)/(x+1) ?
The solution to (x^3-4x^2+x+6)/(x+1) is (x-2)(x-3)