What is (\frac{x^2-3x-10)/(x-3)}{(x+2)/(3x-9)} ?

The solution to (\frac{x^2-3x-10)/(x-3)}{(x+2)/(3x-9)} is 3x-15

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simplify (\frac{x^2-3x-10)/(x-3)}{(x+2)/(3x-9)}

simplify

\frac{\frac{x ^{2} - 3 x - 10}{x - 3}}{\frac{x + 2}{3 x - 9}}

3 x - 15

Solution steps

\frac{\frac{x ^{2} - 3 x - 10}{x - 3}}{\frac{x + 2}{3 x - 9}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 3 x - 10 ) ( 3 x - 9 )}{( x - 3 ) ( x + 2 )}

Cancel

\frac{( x ^{2} - 3 x - 10 ) ( 3 x - 9 )}{( x - 3 ) ( x + 2 )} : (x - 5) \cdot 3

= (x - 5) \cdot 3

Expand

(x - 5) \cdot 3 : 3 x - 15

= 3 x - 15

77 - 37

(3 + 4 i) (3 + 4 i)

\frac{4}{3} \cdot 8

\frac{3}{2} + \frac{5}{3} + \frac{8}{5}

\frac{x ^{3}}{x ^{\frac{1}{2}}}

What is (\frac{x^2-3x-10)/(x-3)}{(x+2)/(3x-9)} ?
The solution to (\frac{x^2-3x-10)/(x-3)}{(x+2)/(3x-9)} is 3x-15