What are the solutions to the equation -x^2+6x-8=0 ?

The solutions to the equation -x^2+6x-8=0 are x=2,x=4

Find the zeros of -x^2+6x-8=0

The zeros of -x^2+6x-8=0 are x=2,x=4

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- x^{2} + 6 x - 8 = 0

x = 2, x = 4

Solution steps

- x^{2} + 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 8) = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2}{2 ( - 1 )}

x = \frac{- 6 + 2}{2 ( - 1 )} : 2

x = \frac{- 6 - 2}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 2, x = 4

4 < - 3 x + 5 < 7

\frac{\frac{3}{4}}{\frac{2}{3}}

\frac{5}{9} \cdot 32

6 s^{2} + 13 s - 63

3 x^{2} - 2 x - 5

What are the solutions to the equation -x^2+6x-8=0 ?
The solutions to the equation -x^2+6x-8=0 are x=2,x=4
Find the zeros of -x^2+6x-8=0
The zeros of -x^2+6x-8=0 are x=2,x=4