What is (4-3i)(-3+6i)-(2-i) ?

The solution to (4-3i)(-3+6i)-(2-i) is 4+34i

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simplify (4-3i)(-3+6i)-(2-i)

simplify

(4 - 3 i) (- 3 + 6 i) - (2 - i)

4 + 34 i

Solution steps

(4 - 3 i) (- 3 + 6 i) - (2 - i)

(4 - 3 i) (- 3 + 6 i) = 6 + 33 i

- (2 - i) = - 2 - (- 1) i

= 6 + 33 i - 2 - (- 1) i

Group like terms

= 33 i - (- 1) i + 6 - 2

Add similar elements:

33 i - (- 1) i = 34 i

= 34 i + 6 - 2

Subtract the numbers:

6 - 2 = 4

= 34 i + 4

Rewrite in standard complex form:

4 + 34 i

= 4 + 34 i

(a + 7) (a - 7)

5 (a^{5} b^{4} - 3 a^{4} b^{3} - 8 a^{3} b^{2})

225 a^{2} - 144 b^{2}

(0.2)^{5}

- \frac{4}{5}