What is (2x^4-x^3+7x-3)/(2x+3) ?

The solution to (2x^4-x^3+7x-3)/(2x+3) is x^3-2x^2+3x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (2x^4-x^3+7x-3)/(2x+3)

simplify

\frac{2 x ^{4} - x ^{3} + 7 x - 3}{2 x + 3}

x^{3} - 2 x^{2} + 3 x - 1

Solution steps

\frac{2 x ^{4} - x ^{3} + 7 x - 3}{2 x + 3}

Factor

2 x^{4} - x^{3} + 7 x - 3 : (2 x + 3) (x^{3} - 2 x^{2} + 3 x - 1)

= \frac{( 2 x + 3 ) ( x ^{3} - 2 x ^{2} + 3 x - 1 )}{2 x + 3}

Cancel the common factor:

2 x + 3

= x^{3} - 2 x^{2} + 3 x - 1

- x^{2} + 12 x - 32

2 x^{3} + x^{2} - 14 x - 7

3^{2 - 1}

(2 x - 1) (3 x - 2)

\frac{m ^{2} - n ^{2}}{m + n}

What is (2x^4-x^3+7x-3)/(2x+3) ?
The solution to (2x^4-x^3+7x-3)/(2x+3) is x^3-2x^2+3x-1