What is the answer to |x^2+2x-4|=4 ?

The answer to |x^2+2x-4|=4 is x=-4\lor x=-2\lor x=0\lor x=2

Solve for x: |x^2+2x-4|=4

The solution is x=-4\lor x=-2\lor x=0\lor x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x - 4 = 4

x = - 4 or x = - 2 or x = 0 or x = 2

Solution steps

x^{2} + 2 x - 4 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 2 x - 4 = - 4 or x^{2} + 2 x - 4 = 4

x^{2} + 2 x - 4 = - 4 or x^{2} + 2 x - 4 = 4

(x = - 2 or x = 0) or (x = - 4 or x = 2)

x = - 4 or x = - 2 or x = 0 or x = 2

6 g + 5 = - 2 (1 + 2 g)

\frac{5 !}{4 !}

∣ x ∣ \geq 1

x^{3} - 19 x + 30

\frac{∣ 4 x - 2 ∣}{6} = 7

What is the answer to |x^2+2x-4|=4 ?
The answer to |x^2+2x-4|=4 is x=-4\lor x=-2\lor x=0\lor x=2
Solve for x: |x^2+2x-4|=4
The solution is x=-4\lor x=-2\lor x=0\lor x=2