What is (2a+1)/(a^2+a-12)+(-2)/(a^2+4a) ?

The solution to (2a+1)/(a^2+a-12)+(-2)/(a^2+4a) is (2a+1)/(a^2+a-12)-2/(a^2+4a)

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simplify (2a+1)/(a^2+a-12)+(-2)/(a^2+4a)

simplify

\frac{2 a + 1}{a ^{2} + a - 12} + \frac{- 2}{a ^{2} + 4 a}

\frac{2 a + 1}{a ^{2} + a - 12} - \frac{2}{a ^{2} + 4 a}

Solution steps

\frac{2 a + 1}{a ^{2} + a - 12} + \frac{- 2}{a ^{2} + 4 a}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 2}{a ^{2} + 4 a} = - \frac{2}{a ^{2} + 4 a}

= \frac{2 a + 1}{a ^{2} + a - 12} - \frac{2}{a ^{2} + 4 a}

2 π \cdot 4

2 π \cdot 2

\frac{x ^{- 2}}{x ^{- 3}}

(x^{2} + 4)^{4}

ln (x^{8})

What is (2a+1)/(a^2+a-12)+(-2)/(a^2+4a) ?
The solution to (2a+1)/(a^2+a-12)+(-2)/(a^2+4a) is (2a+1)/(a^2+a-12)-2/(a^2+4a)