What is (n^2+7n)/(4n^2+28n) ?

The solution to (n^2+7n)/(4n^2+28n) is 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (n^2+7n)/(4n^2+28n)

simplify

\frac{n ^{2} + 7 n}{4 n ^{2} + 28 n}

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\frac{n ^{2} + 7 n}{4 n ^{2} + 28 n}

Factor

n^{2} + 7 n : n (n + 7)

= \frac{n ( n + 7 )}{4 n ^{2} + 28 n}

Factor

4 n^{2} + 28 n : 4 n (n + 7)

= \frac{n ( n + 7 )}{4 n ( n + 7 )}

Cancel the common factor:

n

= \frac{n + 7}{4 ( n + 7 )}

Cancel the common factor:

n + 7

= \frac{1}{4}

∣ x + 7 ∣ \leq 7

lo g_{6} (6)

\frac{x}{1 - x} - \frac{y}{1 - y}

\frac{7 ^{8}}{7 ^{3}}

2 x + 3 \geq 4