What is ((-3q^{-3})^3)/(-6q^{-6)} ?

The solution to ((-3q^{-3})^3)/(-6q^{-6)} is 9/(2q^3)

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simplify ((-3q^{-3})^3)/(-6q^{-6)}

simplify

\frac{( - 3 q ^{- 3} ) ^{3}}{- 6 q ^{- 6}}

\frac{9}{2 q ^{3}}

Solution steps

\frac{( - 3 q ^{- 3} ) ^{3}}{- 6 q ^{- 6}}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 3 q^{- 3})^{3} = - (3 q^{- 3})^{3}

= \frac{- ( 3 q ^{- 3} ) ^{3}}{- 6 q ^{- 6}}

Simplify

(3 q^{- 3})^{3} : 3^{3} \cdot \frac{1}{q ^{9}}

= \frac{- 3 ^{3} \cdot \frac{1}{q ^{9}}}{- 6 q ^{- 6}}

Factor the number:

6 = 3 \cdot 2

= \frac{- 3 ^{3} \cdot \frac{1}{q ^{9}}}{- 3 \cdot 2 q ^{- 6}}

\frac{3 ^{3}}{3} = 3^{2}

= \frac{- 3 ^{2} \cdot \frac{1}{q ^{9}}}{- 2 q ^{- 6}}

Simplify

\frac{- 3 ^{2} \cdot \frac{1}{q ^{9}}}{- 2 q ^{- 6}} : \frac{9}{q ^{3} \cdot 2}

= \frac{9}{q ^{3} \cdot 2}

= \frac{9}{2 q ^{3}}

\frac{2 tan ( x )}{1 - tan ^{2} ( x )} + \frac{1}{2 cos ^{2} ( x ) - 1}

k^{3} + 1

(24)^{2}

(2 x^{6} y^{2}) (2 x^{3} - y^{7} z^{2})

What is ((-3q^{-3})^3)/(-6q^{-6)} ?
The solution to ((-3q^{-3})^3)/(-6q^{-6)} is 9/(2q^3)