What is (4x^2-7)+(6x^2-5) ?

The solution to (4x^2-7)+(6x^2-5) is 10x^2-12

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simplify (4x^2-7)+(6x^2-5)

simplify

(4 x^{2} - 7) + (6 x^{2} - 5)

10 x^{2} - 12

Solution steps

(4 x^{2} - 7) + (6 x^{2} - 5)

Simplify

(4 x^{2} - 7) + (6 x^{2} - 5) : 4 x^{2} - 7 + 6 x^{2} - 5

= 4 x^{2} - 7 + 6 x^{2} - 5

Group like terms

= 4 x^{2} + 6 x^{2} - 7 - 5

Add similar elements:

4 x^{2} + 6 x^{2} = 10 x^{2}

= 10 x^{2} - 7 - 5

Subtract the numbers:

- 7 - 5 = - 12

= 10 x^{2} - 12

\frac{k ( k + 1 ) ( k + 2 )}{3} + (k + 1) (k + 2)

12 j^{6}

- 5 - (- 10)

(- 3)^{2} + (- 1)^{2}

\frac{6}{x ^{2} - 4} + \frac{2}{x ^{2} - 5 x + 6}