What is (2v^2+10v-48)/(8v+64) ?

The solution to (2v^2+10v-48)/(8v+64) is (v-3)/4

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simplify (2v^2+10v-48)/(8v+64)

simplify

\frac{2 v ^{2} + 10 v - 48}{8 v + 64}

\frac{v - 3}{4}

Solution steps

\frac{2 v ^{2} + 10 v - 48}{8 v + 64}

Factor

2 v^{2} + 10 v - 48 : 2 (v - 3) (v + 8)

= \frac{2 ( v - 3 ) ( v + 8 )}{8 v + 64}

Factor

8 v + 64 : 8 (v + 8)

= \frac{2 ( v - 3 ) ( v + 8 )}{8 ( v + 8 )}

Cancel the common factor:

v + 8

= \frac{2 ( v - 3 )}{8}

Factor the number:

8 = 2 \cdot 4

= \frac{2 ( v - 3 )}{2 \cdot 4}

Cancel the common factor:

2

= \frac{v - 3}{4}

(a + 4) (a - 5)

(x^{3}) (- 9 x)

81 + - 6 - 64 + - 150

(a^{2} \cdot a^{2} \cdot a^{2})^{3}

- \frac{1}{5}

What is (2v^2+10v-48)/(8v+64) ?
The solution to (2v^2+10v-48)/(8v+64) is (v-3)/4