What is factor 4x^3+7x^2-28x-49 ?

The solution to factor 4x^3+7x^2-28x-49 is (4x+7)(x^2-7)

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factor 4x^3+7x^2-28x-49

factor

4 x^{3} + 7 x^{2} - 28 x - 49

(4 x + 7) (x^{2} - 7)

Solution steps

4 x^{3} + 7 x^{2} - 28 x - 49

= (4 x^{3} + 7 x^{2}) + (- 28 x - 49)

Factor out

x^{2}

from

4 x^{3} + 7 x^{2} : x^{2} (4 x + 7)

Factor out

- 7

from

- 28 x - 49 : - 7 (4 x + 7)

= x^{2} (4 x + 7) - 7 (4 x + 7)

Factor out common term

4 x + 7

= (4 x + 7) (x^{2} - 7)

\frac{- 5 x ^{3}}{5 x + 8} + \frac{6 x ^{3}}{5 x + 8}

(5 q^{4} r^{2})^{5}

0.1 8^{2}

\frac{72}{100}

(\frac{2 ^{0} \cdot 5 ^{2}}{3})^{0}

What is factor 4x^3+7x^2-28x-49 ?
The solution to factor 4x^3+7x^2-28x-49 is (4x+7)(x^2-7)