What are the solutions to the equation 3-x^2=7-5x ?

The solutions to the equation 3-x^2=7-5x are x=1,x=4

Find the zeros of 3-x^2=7-5x

The zeros of 3-x^2=7-5x are x=1,x=4

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3 - x^{2} = 7 - 5 x

x = 1, x = 4

Solution steps

3 - x^{2} = 7 - 5 x

Move

5 x

to the left side

3 - x^{2} + 5 x = 7

Move

7

to the left side

- x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 4) = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 ( - 1 )}, x_{2} = \frac{- 5 - 3}{2 ( - 1 )}

x = \frac{- 5 + 3}{2 ( - 1 )} : 1

x = \frac{- 5 - 3}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 1, x = 4

0 < ∣ 2 - 3 x ∣ < 1

4 \cdot \frac{3 π}{2}

- 4 - 6 y \geq 26

9 x^{2} + 21 x - 8

\frac{x}{3} - 5 = 4

What are the solutions to the equation 3-x^2=7-5x ?
The solutions to the equation 3-x^2=7-5x are x=1,x=4
Find the zeros of 3-x^2=7-5x
The zeros of 3-x^2=7-5x are x=1,x=4