What is (8y^2-5y+7)-(2y^2+7y+11) ?

The solution to (8y^2-5y+7)-(2y^2+7y+11) is 6y^2-12y-4

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simplify (8y^2-5y+7)-(2y^2+7y+11)

simplify

(8 y^{2} - 5 y + 7) - (2 y^{2} + 7 y + 11)

6 y^{2} - 12 y - 4

Solution steps

(8 y^{2} - 5 y + 7) - (2 y^{2} + 7 y + 11)

Apply rule:

(a) = a

(8 y^{2} - 5 y + 7) = 8 y^{2} - 5 y + 7

= 8 y^{2} - 5 y + 7 - (2 y^{2} + 7 y + 11)

Apply the distributive law:

- (a + b) = - a - b

- (2 y^{2} + 7 y + 11) = - 2 y^{2} - 7 y - 11

= 8 y^{2} - 5 y + 7 - 2 y^{2} - 7 y - 11

Group like terms

= 8 y^{2} - 2 y^{2} - 5 y - 7 y + 7 - 11

Add similar elements:

8 y^{2} - 2 y^{2} = 6 y^{2}

= 6 y^{2} - 5 y - 7 y + 7 - 11

Add similar elements:

- 5 y - 7 y = - 12 y

= 6 y^{2} - 12 y + 7 - 11

Subtract the numbers:

7 - 11 = - 4

= 6 y^{2} - 12 y - 4

(2 y - 2)^{2}

\frac{a - b}{( a - b ) ^{2}} \cdot \frac{a + b}{a ^{2} - b ^{2}}

2 x^{2} - 12 x + 20

a^{7} - 128

What is (8y^2-5y+7)-(2y^2+7y+11) ?
The solution to (8y^2-5y+7)-(2y^2+7y+11) is 6y^2-12y-4