What are the solutions to the equation 8x(x+2)=0 ?

The solutions to the equation 8x(x+2)=0 are x=0,x=-2

Find the zeros of 8x(x+2)=0

The zeros of 8x(x+2)=0 are x=0,x=-2

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8 x (x + 2) = 0

x = 0, x = - 2

Solution steps

8 x (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

x^{2} - 12 x + 22 = 0

5 y^{2} = 30 y

C = \frac{5}{9} (41 - 32)

a^{- 1}

2 n + 7 \geq 27 or 3 + 3 n \leq 30

What are the solutions to the equation 8x(x+2)=0 ?
The solutions to the equation 8x(x+2)=0 are x=0,x=-2
Find the zeros of 8x(x+2)=0
The zeros of 8x(x+2)=0 are x=0,x=-2