What is (x^2+3x+2)/(x^2-2x+1)-(3x+3)/(x^2-2x+1) ?

The solution to (x^2+3x+2)/(x^2-2x+1)-(3x+3)/(x^2-2x+1) is (x+1)/(x-1)

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simplify (x^2+3x+2)/(x^2-2x+1)-(3x+3)/(x^2-2x+1)

simplify

\frac{x ^{2} + 3 x + 2}{x ^{2} - 2 x + 1} - \frac{3 x + 3}{x ^{2} - 2 x + 1}

\frac{x + 1}{x - 1}

Solution steps

\frac{x ^{2} + 3 x + 2}{x ^{2} - 2 x + 1} - \frac{3 x + 3}{x ^{2} - 2 x + 1}

Join

\frac{x ^{2} + 3 x + 2}{x ^{2} - 2 x + 1} - \frac{3 x + 3}{x ^{2} - 2 x + 1} : \frac{x + 1}{x - 1}

= \frac{x + 1}{x - 1}

(9 + 5 i) (4 - 2 i)

(3 x + 2) (x - 3)

lo g_{\frac{1}{8}} ((\frac{1}{32})^{- 3})

(- 3 - 3 - 3)^{2}

What is (x^2+3x+2)/(x^2-2x+1)-(3x+3)/(x^2-2x+1) ?
The solution to (x^2+3x+2)/(x^2-2x+1)-(3x+3)/(x^2-2x+1) is (x+1)/(x-1)