What is (4x^2-3x+2)-(2x^2+5x-7) ?

The solution to (4x^2-3x+2)-(2x^2+5x-7) is 2x^2-8x+9

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simplify (4x^2-3x+2)-(2x^2+5x-7)

simplify

(4 x^{2} - 3 x + 2) - (2 x^{2} + 5 x - 7)

2 x^{2} - 8 x + 9

Solution steps

(4 x^{2} - 3 x + 2) - (2 x^{2} + 5 x - 7)

Apply rule:

(a) = a

(4 x^{2} - 3 x + 2) = 4 x^{2} - 3 x + 2

= 4 x^{2} - 3 x + 2 - (2 x^{2} + 5 x - 7)

Apply the distributive law:

- (a + b) = - a - b

- (2 x^{2} + 5 x - 7) = - 2 x^{2} - 5 x + 7

= 4 x^{2} - 3 x + 2 - 2 x^{2} - 5 x + 7

Group like terms

= 4 x^{2} - 2 x^{2} - 3 x - 5 x + 2 + 7

Add similar elements:

4 x^{2} - 2 x^{2} = 2 x^{2}

= 2 x^{2} - 3 x - 5 x + 2 + 7

Add similar elements:

- 3 x - 5 x = - 8 x

= 2 x^{2} - 8 x + 2 + 7

Add the numbers:

2 + 7 = 9

= 2 x^{2} - 8 x + 9

(- 3 + i) + (6 + 5 i)

\frac{7}{8} \div \frac{2}{3}

\frac{2 ( \frac{12}{5} )}{1 - ( \frac{12}{5} ) ^{2}}

\frac{8 x ^{8} y ^{8}}{x ^{5} y ^{5}}

What is (4x^2-3x+2)-(2x^2+5x-7) ?
The solution to (4x^2-3x+2)-(2x^2+5x-7) is 2x^2-8x+9