What is (((4a)/5)^2)/((\frac{a^2){a+1}-1/(a+1))} ?

The solution to (((4a)/5)^2)/((\frac{a^2){a+1}-1/(a+1))} is (16a^2)/(25(a-1))

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simplify (((4a)/5)^2)/((\frac{a^2){a+1}-1/(a+1))}

simplify

\frac{( \frac{4 a}{5} ) ^{2}}{( \frac{a ^{2}}{a + 1} - \frac{1}{a + 1} )}

\frac{16 a ^{2}}{25 ( a - 1 )}

Solution steps

\frac{( \frac{4 a}{5} ) ^{2}}{\frac{a ^{2}}{a + 1} - \frac{1}{a + 1}}

Simplify

(\frac{4 a}{5})^{2} : \frac{16 a ^{2}}{25}

= \frac{\frac{16 a ^{2}}{25}}{\frac{a ^{2}}{a + 1} - \frac{1}{a + 1}}

Join

\frac{a ^{2}}{a + 1} - \frac{1}{a + 1} : a - 1

= \frac{\frac{16 a ^{2}}{25}}{a - 1}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{16 a ^{2}}{25 ( a - 1 )}

x (x + 4) (x - 3)

3 x - 7 y + 5 x + 4 y

21 6^{3}

22 \cdot 3

(x + 2) (2 x - 3)

What is (((4a)/5)^2)/((\frac{a^2){a+1}-1/(a+1))} ?
The solution to (((4a)/5)^2)/((\frac{a^2){a+1}-1/(a+1))} is (16a^2)/(25(a-1))