What is (\frac{x^2-4)/(x-8)}{(x-2)} ?

The solution to (\frac{x^2-4)/(x-8)}{(x-2)} is (x+2)/(x-8)

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simplify (\frac{x^2-4)/(x-8)}{(x-2)}

simplify

\frac{\frac{x ^{2} - 4}{x - 8}}{( x - 2 )}

\frac{x + 2}{x - 8}

Solution steps

\frac{\frac{x ^{2} - 4}{x - 8}}{x - 2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{x ^{2} - 4}{( x - 8 ) ( x - 2 )}

Cancel

\frac{x ^{2} - 4}{( x - 8 ) ( x - 2 )} : \frac{x + 2}{x - 8}

= \frac{x + 2}{x - 8}

5 \cdot (- 7)

\frac{169}{3}

2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

1 0^{l o g_{10} (13)}

\frac{9}{5 + 2}

What is (\frac{x^2-4)/(x-8)}{(x-2)} ?
The solution to (\frac{x^2-4)/(x-8)}{(x-2)} is (x+2)/(x-8)