What are the solutions to the equation 3=x-3x^2 ?

The solutions to the equation 3=x-3x^2 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6

Find the zeros of 3=x-3x^2

The zeros of 3=x-3x^2 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6

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3 = x - 3 x^{2}

x = \frac{1}{6} - i \frac{35}{6}, x = \frac{1}{6} + i \frac{35}{6}

Solution steps

3 = x - 3 x^{2}

Switch sides

x - 3 x^{2} = 3

Move

3

to the left side

x - 3 x^{2} - 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

Simplify

1^{2} - 4 (- 3) (- 3) : 35 i

x_{1, 2} = \frac{- 1 \pm 35 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 35 i}{2 ( - 3 )}, x_{2} = \frac{- 1 - 35 i}{2 ( - 3 )}

x = \frac{- 1 + 35 i}{2 ( - 3 )} : \frac{1}{6} - i \frac{35}{6}

x = \frac{- 1 - 35 i}{2 ( - 3 )} : \frac{1}{6} + i \frac{35}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} - i \frac{35}{6}, x = \frac{1}{6} + i \frac{35}{6}

lo g_{6} (4)

8 - ∣ 2 x + 9 ∣ \leq 5

\frac{3 x}{7} + \frac{2}{7} = 2

(x - 2) (x + 2) = 0

16 a^{5} b^{3} + 32 a^{4} b

What are the solutions to the equation 3=x-3x^2 ?
The solutions to the equation 3=x-3x^2 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6
Find the zeros of 3=x-3x^2
The zeros of 3=x-3x^2 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6