What is (1+7i)(9+3i)-(4+2i) ?

The solution to (1+7i)(9+3i)-(4+2i) is -16+64i

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simplify (1+7i)(9+3i)-(4+2i)

simplify

(1 + 7 i) (9 + 3 i) - (4 + 2 i)

- 16 + 64 i

Solution steps

(1 + 7 i) (9 + 3 i) - (4 + 2 i)

(1 + 7 i) (9 + 3 i) = - 12 + 66 i

- (4 + 2 i) = - 4 - 2 i

= - 12 + 66 i - 4 - 2 i

Group like terms

= 66 i - 2 i - 12 - 4

Add similar elements:

66 i - 2 i = 64 i

= 64 i - 12 - 4

Subtract the numbers:

- 12 - 4 = - 16

= 64 i - 16

Rewrite in standard complex form:

- 16 + 64 i

= - 16 + 64 i

15 \times 10

\frac{5}{4} - \frac{3}{2}

3 (x - 3)^{2}

(x^{2} + y^{2} - 1)^{3} - x^{2} y^{3}

2 (\frac{1}{x})