What is factor-2x^4+20x^3+48x^2 ?

The solution to factor-2x^4+20x^3+48x^2 is -2x^2(x+2)(x-12)

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factor-2x^4+20x^3+48x^2

factor

- 2 x^{4} + 20 x^{3} + 48 x^{2}

- 2 x^{2} (x + 2) (x - 12)

Solution steps

- 2 x^{4} + 20 x^{3} + 48 x^{2}

Factor out common term

2 x^{2} : 2 x^{2} (- x^{2} + 10 x + 24)

= 2 x^{2} (- x^{2} + 10 x + 24)

Factor

- x^{2} + 10 x + 24 : - (x + 2) (x - 12)

= - 2 x^{2} (x + 2) (x - 12)

(3 c - 4) (2 c^{2} - 5 c + 7)

(3 x - 2) (2 x - 3)

\frac{x ^{2} - 5 x - 24}{x ^{2} - 15 x + 56}

2 x - 5 x + 10 x - 6 x + x

\frac{( 3 x + 9 )}{( 5 x ^{2} y )} \cdot \frac{( x ^{3} y ^{2} )}{( 2 x + 6 )}

What is factor-2x^4+20x^3+48x^2 ?
The solution to factor-2x^4+20x^3+48x^2 is -2x^2(x+2)(x-12)