What is factor x^4+4x^3+6x^2+4x+1 ?

The solution to factor x^4+4x^3+6x^2+4x+1 is (x+1)^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor x^4+4x^3+6x^2+4x+1

factor

x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1

(x + 1)^{4}

Solution steps

x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1

Use the rational root theorem

= (x + 1) \frac{x ^{4} + 4 x ^{3} + 6 x ^{2} + 4 x + 1}{x + 1}

\frac{x ^{4} + 4 x ^{3} + 6 x ^{2} + 4 x + 1}{x + 1} = x^{3} + 3 x^{2} + 3 x + 1

= (x + 1) (x^{3} + 3 x^{2} + 3 x + 1)

Factor

x^{3} + 3 x^{2} + 3 x + 1 : (x + 1)^{3}

= (x + 1) (x + 1)^{3}

Simplify

(x + 1) (x + 1)^{3} : (x + 1)^{4}

= (x + 1)^{4}

(b^{2})^{3}

- 8^{\frac{5}{3}}

\frac{1 - 2}{1 + 2}

\frac{( x - 3 ) ( x + 2 )}{x ^{2} - 9} \cdot \frac{5}{x + 2}

\frac{9 x ^{5} + 9 x ^{4} + 45 x ^{3}}{9 x ^{2}}

What is factor x^4+4x^3+6x^2+4x+1 ?
The solution to factor x^4+4x^3+6x^2+4x+1 is (x+1)^4