What is (5r^{-1})/(4(r^{-1))^2} ?

The solution to (5r^{-1})/(4(r^{-1))^2} is (5r)/4

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simplify (5r^{-1})/(4(r^{-1))^2}

simplify

\frac{5 r ^{- 1}}{4 ( r ^{- 1} ) ^{2}}

\frac{5 r}{4}

Solution steps

\frac{5 r ^{- 1}}{4 ( r ^{- 1} ) ^{2}}

Simplify

5 r^{- 1} : \frac{5}{r}

= \frac{\frac{5}{r}}{4 ( r ^{- 1} ) ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{5}{r \cdot 4 ( r ^{- 1} ) ^{2}}

Simplify

r \cdot 4 (r^{- 1})^{2} : \frac{4}{r}

= \frac{5}{\frac{4}{r}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{5 r}{4}

x^{4} - 5 x^{3} + 5 x^{2} + 5 x - 6

ln (e^{9 x})

2 x^{9}

\frac{21}{18}

(- 9 + - 16) (3 - 4 i)

What is (5r^{-1})/(4(r^{-1))^2} ?
The solution to (5r^{-1})/(4(r^{-1))^2} is (5r)/4