What is (x^2+11x+28)/(x^2+x-12) ?

The solution to (x^2+11x+28)/(x^2+x-12) is (x+7)/(x-3)

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simplify (x^2+11x+28)/(x^2+x-12)

simplify

\frac{x ^{2} + 11 x + 28}{x ^{2} + x - 12}

\frac{x + 7}{x - 3}

Solution steps

\frac{x ^{2} + 11 x + 28}{x ^{2} + x - 12}

Factor

x^{2} + 11 x + 28 : (x + 4) (x + 7)

= \frac{( x + 4 ) ( x + 7 )}{x ^{2} + x - 12}

Factor

x^{2} + x - 12 : (x - 3) (x + 4)

= \frac{( x + 4 ) ( x + 7 )}{( x - 3 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{x + 7}{x - 3}

\frac{- 10 h ^{6}}{( 2 h ^{- 3} ) ^{5}}

- x^{12}

(x - 3 y)^{4}

(n^{2} - 2 n + 1) (n^{2} - 1)

\frac{8 x y}{2 x ^{3} y ^{7}}

What is (x^2+11x+28)/(x^2+x-12) ?
The solution to (x^2+11x+28)/(x^2+x-12) is (x+7)/(x-3)