What is n+n/2+(3n)/4+(4n)/5-n/(20) ?

The solution to n+n/2+(3n)/4+(4n)/5-n/(20) is 3n

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simplify n+n/2+(3n)/4+(4n)/5-n/(20)

simplify

n + \frac{n}{2} + \frac{3 n}{4} + \frac{4 n}{5} - \frac{n}{20}

3 n

Solution steps

n + \frac{n}{2} + \frac{3 n}{4} + \frac{4 n}{5} - \frac{n}{20}

Join

\frac{n}{2} + \frac{3 n}{4} + \frac{4 n}{5} - \frac{n}{20} : \frac{40 n}{20}

= n + \frac{40 n}{20}

Apply the fraction rule:

a + \frac{b}{c} = \frac{a c + b}{c}

= \frac{n \cdot 20 + 40 n}{20}

Add similar elements:

n \cdot 20 + 40 n = 60 n

= \frac{60 n}{20}

Divide the numbers:

\frac{60}{20} = 3

= 3 n

\frac{1}{4} \cdot \frac{3}{2}

5 \frac{2}{7}

10 2^{4} - 3^{6}

y^{2} - 10 y

\frac{2 x ^{2} y ^{2}}{8 x ^{5} y ^{7}}

What is n+n/2+(3n)/4+(4n)/5-n/(20) ?
The solution to n+n/2+(3n)/4+(4n)/5-n/(20) is 3n