What is expand (x+2)(x-3)(x+1) ?

The solution to expand (x+2)(x-3)(x+1) is x^3-7x-6

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expand (x+2)(x-3)(x+1)

expand

(x + 2) (x - 3) (x + 1)

x^{3} - 7 x - 6

Solution steps

(x + 2) (x - 3) (x + 1)

Expand

(x + 2) (x - 3) (x + 1) : (x^{2} - x - 6) (x + 1)

= (x^{2} - x - 6) (x + 1)

Distribute parentheses

= x^{2} x + x^{2} \cdot 1 - xx - x \cdot 1 - 6 x - 6 \cdot 1

Simplify

x^{2} x + x^{2} \cdot 1 - xx - x \cdot 1 - 6 x - 6 \cdot 1 : x^{3} - 7 x - 6

= x^{3} - 7 x - 6

\frac{5 a ^{2} + 8 ab - 21 b ^{2}}{a + 3 b}

2 (\frac{1}{3})^{x} - 1

2 x (5 x - 2)

- y^{2} + 4 y - 4

2 x + 8 y

What is expand (x+2)(x-3)(x+1) ?
The solution to expand (x+2)(x-3)(x+1) is x^3-7x-6