What are the solutions to the equation 25x^2+49=70x ?

The solutions to the equation 25x^2+49=70x are x= 7/5

Find the zeros of 25x^2+49=70x

The zeros of 25x^2+49=70x are x= 7/5

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25 x^{2} + 49 = 70 x

x = \frac{7}{5}

Solution steps

25 x^{2} + 49 = 70 x

Move

70 x

to the left side

25 x^{2} + 49 - 70 x = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} - 70 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 25 \cdot 49}{2 \cdot 25}

(- 70)^{2} - 4 \cdot 25 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 70 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 70 )}{2 \cdot 25}

\frac{- ( - 70 )}{2 \cdot 25} = \frac{7}{5}

x = \frac{7}{5}

The solution to the quadratic equation is:

x = \frac{7}{5}

\frac{x + 1}{8} = 8

2 x^{2} + 5 x - 3 < 0

\frac{3}{4} x + 7 = 22

x - \frac{4}{7} = - \frac{2}{5}

0.75 a = - 9

What are the solutions to the equation 25x^2+49=70x ?
The solutions to the equation 25x^2+49=70x are x= 7/5
Find the zeros of 25x^2+49=70x
The zeros of 25x^2+49=70x are x= 7/5