What are the solutions to the equation x^2+8x-1=0 ?

The solutions to the equation x^2+8x-1=0 are x=-4+sqrt(17),x=-4-sqrt(17)

Find the zeros of x^2+8x-1=0

The zeros of x^2+8x-1=0 are x=-4+sqrt(17),x=-4-sqrt(17)

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x^{2} + 8 x - 1 = 0

x = - 4 + 17, x = - 4 - 17

Decimal Notation

x = 0.12310 \dots, x = - 8.12310 \dots

Solution steps

x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 1) = 217

x_{1, 2} = \frac{- 8 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 17}{2 \cdot 1}

x = \frac{- 8 + 2 17}{2 \cdot 1} : - 4 + 17

x = \frac{- 8 - 2 17}{2 \cdot 1} : - 4 - 17

The solutions to the quadratic equation are:

x = - 4 + 17, x = - 4 - 17

4 x - 14 = x - 1 + x + 7

\frac{1}{2 ^{1}}

\frac{6 a ^{2} + 21 a}{3 a ^{2}}

- 2 \leq x < 3

- \frac{1}{2} + \frac{3}{4}

What are the solutions to the equation x^2+8x-1=0 ?
The solutions to the equation x^2+8x-1=0 are x=-4+sqrt(17),x=-4-sqrt(17)
Find the zeros of x^2+8x-1=0
The zeros of x^2+8x-1=0 are x=-4+sqrt(17),x=-4-sqrt(17)