What are the solutions to the equation 49x^2=25 ?

The solutions to the equation 49x^2=25 are x= 5/7 ,x=-5/7

Find the zeros of 49x^2=25

The zeros of 49x^2=25 are x= 5/7 ,x=-5/7

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49 x^{2} = 25

x = \frac{5}{7}, x = - \frac{5}{7}

Decimal Notation

x = 0.71428 \dots, x = - 0.71428 \dots

Solution steps

49 x^{2} = 25

Divide both sides by

49

x^{2} = \frac{25}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{49}, x = - \frac{25}{49}

\frac{25}{49} = \frac{5}{7}

- \frac{25}{49} = - \frac{5}{7}

x = \frac{5}{7}, x = - \frac{5}{7}

\frac{4 X - 5}{7 X} < 2

∣ x - 9 ∣ < 0

\frac{m}{3} - 3 \leq - 6

f (g^{- 1} (\frac{15}{17}))

28 x^{3} + 88 x^{2} - 37 x - 7

What are the solutions to the equation 49x^2=25 ?
The solutions to the equation 49x^2=25 are x= 5/7 ,x=-5/7
Find the zeros of 49x^2=25
The zeros of 49x^2=25 are x= 5/7 ,x=-5/7